15 Oct
2015
15 Oct
'15
12:59 p.m.
Solve for the roots of the derivative polynomial. These are the eigenvalues of M'. String them along the diagonal, and make an arbitrary similarity transformation. If M' has repeated eigenvalues, Jordan blocks are also possible. -- Gene From: Mike Stay <metaweta@gmail.com> To: math-fun <math-fun@mailman.xmission.com> Sent: Thursday, October 15, 2015 9:36 AM Subject: [math-fun] Characteristic polynomial question What operation on a matrix M gives a new matrix M' whose characteristic polynomial is the derivative of the char. poly. of M? -- Mike Stay - metaweta@gmail.com http://www.cs.auckland.ac.nz/~mike http://reperiendi.wordpress.com