25 Oct
2015
25 Oct
'15
2:55 p.m.
Regarding Mobius bands, Dan's remark (If differentiability is assumed to be only C^1, then the answer is inf{h}
= 0, because of the Nash-Kuiper isometric embedding theorem. It's very hard to imagine just how this works.)
makes me wonder what the situation is for PL embeddings. Can a clever origamist turn ANY rectangle into a Mobius band? Jim Propp