Mensaje citado por: mcintosh@servidor.unam.mx:
wrong!
meesa wrong too. if QR = w RQ then RQ = w^{-1} QR and so w better not be zero. if w^3 = 1 holds, the rest of my comment applies as posted, but then it is silly to use it to conclude that w = (cube root of 1). In fact w could be anything but zero, but context dictates that cube root. Mensaje citado por: Michael Reid <reid@math.arizone.edu>:
... which is the continuous cohomology group ...
Ah, yes ... those cohomologies. Another application of exotic quaternions is to the symmetry group of a magnetic lattice; this and related things are the subject of some articles by J. Zak in Journal of Mathematical Physics and elsewhere.
divisors of zero
how are you going to avoid them if you have nontrivial matrices and orthogonal idempotents? - hvm ------------------------------------------------- Obtén tu correo en www.correo.unam.mx UNAMonos Comunicándonos