RE: [math-fun] n^e and pi(n)

At 10:33 PM 1/24/2004, Alec Mihailovs wrote:

I didn't believe the original posting and I couldn't believe this reply! Have you ever heard about the asymptotic pi(n)~n/ln(n)? How it can be smaller than n^e for e>0? It is greater than n^e for any e<1!

Sorry, I misread the original. I thought he was using e - the base of natural log.