17 Mar
2004
17 Mar
'04
3:04 p.m.
It's (or at least, one flavor of it) based on the product rule: for functions f(x) and g(x), (fg)' = f'g + fg'. So with numbers, (ab)' = a'b + ab'. It only holds for natural numbers, due to the fundamental theorem of arithmetic. One can show that 1' = 0, and p' = 1 for any prime p. Then, for example, 6' = (2x3)' = 2'x3 + 2x3' = 1x3 + 2x1 = 5. You can find more details here: Ufnarovski, V., "How to Differentiate a Number," Journal of Integer Sequences, vol 6, 2003. Kerry Mitchell -- lkmitch@att.net www.fractalus.com/kerry