6 Apr
2015
6 Apr
'15
5:47 p.m.
On 07/04/2015 00:11, Mike Speciner wrote:
Well, it actually is the same circumcircle if you have AB be common to both triangles (ABC and ABC') if you have C and C' on opposite sides of chord AB.
Oh, neat. I hadn't thought of drawing it that way. (This may reveal that I didn't read every message in this thread in detail and draw diagrams as I did so. Sorry.) -- g