[math-fun] Fwd: Sure looks like 1/Log@4

---------- Forwarded message --------- To: Wolfram Technical Support *Out*[1013]= Sum[1/(n*Log[n]) - 1/(2*n*Log[2*n]) - 1/((-1 + 2*n)*Log[-1 + 2*n]), {n, 2,∞}] In[1015]:= 1/Log@4. Out[1015]= 0.721347520444482 In[1016]:= N[%1013, 22] Out[1016]= 0.7213475204444817036800 —Bill