[math-fun] hypergeometric solution of quintic

Of course 4F3(x) and indeed any pFq(x) with p<=q+1, is defined for all complex x except for a set of measure zero, via analytic continuation. And this particular 4F3 is of course an algebraic function which makes that obvious. The solution of the quintic via this method is however nuts in the sense that you will be far better off solving quintic by typical numerical methods, than by applying the "exact solution," i.e. you will obtain more digits faster. Indeed the best way to evaluate that 4F3 is by solving the quintic, not the other way round. -- Warren D. Smith http://RangeVoting.org <-- add your endorsement (by clicking "endorse" as 1st step)