Re: [math-fun] Only two operations inserted between digits of N

736 = 7+3^6 2502 = 2+50^2 34425 = 3^4*425 39343 = 39+34^3

Are there many more integers N which give back N if we insert only two "operations" somewhere between the digits of N?

there are no more 5-digit solutions. the only four 6-digit solutions are: 250002 = 2 + 500 ^ 02 (if you allow leading 0's) 312325 = 31 ^ 2 * 325 344250 = 3 ^ 4 * 4250 (obviously infinitely many like this) 492205 = 49 ^ 2 * 205 erich