6 Jan
2007
6 Jan
'07
4:51 p.m.
On 1/6/07, Michael Kleber <michael.kleber@gmail.com> wrote:
Is the altitude of an integer-edged tetrahedron always degree <=2 over the rationals, as for triangles? That would make clear why these are so common.
The squared base area and the squared volume are both polynomials in the squared edges; 3x altitude equals volume divided by base. Hence altitude equals square root of a rational. WFL