11 Dec
2019
11 Dec
'19
12:16 p.m.
The odds of picking at random the four letters F, O, U, R in this sentence and in that order are Y out of Z. EA: "The 'FOUR' letter challenge is still open!" If Y = "one" and Z = "one hundred twenty-seven thousand, seven hundred seventy-six", I make the total letter count of the sentence to be 132, with 4 of 'f', 11 of 'o', 6 of 'u', and 9 of 'r'. If the probability is 4*11*6*9/132^4, then we have a hit.