10 Feb
2014
10 Feb
'14
10:24 a.m.
Ok, what do you propose for gcd(0,0) ? At 09:20 AM 2/10/2014, Mike Speciner wrote:
And, as I recall, many early computers said n/0 = n.
If gcd(0,0) = 0, then it is not universally true that gcd(a,b)=gcd(a-b,b).
On 2014-02-10 11:06, Henry Baker wrote:
At 07:08 AM 2/10/2014, Mike Speciner wrote:
gcd(0,0) = 0 ???
I always thought a positive integer was prime iff it had exactly two positive integer divisors. Common Lisp & Maxima say gcd(0,0)=0.