Me neither. There is, however, a very natural 4-dimensional set that combines both the standard Mandelbrot set and all of its corresponding Julia sets into a single entity. Let one plane determine c0, and an orthogonal plane determine c1. The product is 4-dimensional, and the iteration is: z(0) = c0 z(i) = z(i-1)^2 + c1 The planar slice obtained by setting c0 to 0 and varying c1 is the Mandelbrot set. The planar slice obtained by setting c1 to some constant and varying c0 is the Julia set corresponding to c1. Unfortunately, having a 2-dimensional retina makes it difficult for me to visualize such a set. Being three dimensional can be very frustrating. Tom
I cannot understand the basis for the assumption that there is a "real" 3D Mandelbrot set.
--Dan
Sometimes the brain has a mind of its own.
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