11 Feb
2003
11 Feb
'03
2:22 p.m.
At 03:36 PM 2/11/2003, Dan Hoey wrote:
Oops, let's stick with:
Second, letting f(n) = (u(n)/21.6) - floor(u(n)/21.6), for what n in 1000...1999 is .5 <= f(n) < .55?
There should only be four or five answers.
I get 1091 0.527777777777778 - 19/36 1210 0.537037037037037 - 29/54 1730 0.500000000000000 - 1/2 1748 0.509259259259259 - 55/108 1947 0.509259259259259 - 55/108