22 Apr
2004
22 Apr
'04
7:48 p.m.
Ack! I'm not doing very well today. I wrote: (more or less) prime partitions -> Melzak -> zeta function But Melzak's transform leaves the sequence the same, and there's certainly more than one way to partition most numbers into sums of primes. I guess the transform I'm looking for in this case is one that takes prod (k in S) 1/(1-x^k) to prod(k in S) 1/(1-k^x) rather than sum (n in N) a_n x^n to sum(n in N) a_n n^x -- Mike Stay staym@clear.net.nz http://www.cs.auckland.ac.nz/~msta039