Re: [math-fun] Cutting a pie ...

The sharp-eyed among you may have noted that my denominator 240 solution for f(5) was spurious, since it has 10 parts and not 9. The f(5) solutions are (after multiplying by 60):

(1, 5, 6, 11, 13, 17, 19, 23, 24)/2 If you’re trying to catch us asleep again, then you've failed. That 6 should be a 7.

-Veit P.S. Does your software let you know how many solutions there are for each partition? If so, it could explain the rather non-uniform rates that divide-and-concur finds them.