Let A(n) be the number of ways of expressing 4/n as the sum of three integer reciprocals, where the mere permutation of a sum is regarded as not making a difference. Plainly 4/1 = 4 cannot be expressed as the sum of three reciprocals, so A(1) = 0. 4/2 = 2 = 1/1 + 1/2 + 1/2, and there are no other solutions, so A(2) = 1. 4/3 = 1 + 1/4 + 1/12 = 1+ 1/6 + 1/6 = 1/2 + 1/2 + 1/3; I am pretty sure that A(3) = 3. The Erdős–Straus conjecture is that A(n) > 0 for all n > 1. Of course I wanted to know if A was in OEIS. I calculated a few more terms, and what I had was 0, 1, 3, 3, 2, 8 ... I was pretty confident in my enumeration, so I calculated enough entries, and discovered to my surprise that the sequence was missing. Then I searched for "Straus", and quickly found A192787, which claims to be my A. The trouble is, A192787(4) = 4, and I say A(4) = 3. Bear with me while I list my solutions, and then somebody tell me what I missed. 4/4 = 1, so the problem is to partition 1 into three reciprocals. I have the following solutions: 1/2 + 1/3 + 1/6 1/2 + 1/4 + 1/4 1/3 + 1/3 + 1/3 A192787 seems to be claiming that I missed one. Charles R. Greathouse IV was the sequence author, and I think he's a funster, so, Charles, if you're listening, can you tell me the missing dissection?