(%i1) (3/2)^12=2^7; 531441 (%o1) ------ = 128 4096 (%i2) %*4096; (%o2) 531441 = 524288 (%i3) lhs(%)-rhs(%); (%o3) 7153 (%i4) factor(%); (%o4) 23 311 (%i5) mod(531441,23); (%o5) 3 (%i6) mod(524288,23); (%o6) 3 (%i7) So what about (mod 23) or (mod 311) ? Can something like this be made to work? At 05:27 PM 12/3/2014, Dan Asimov wrote:
That should be:
So we can never have (3/2)^12 = 2^7, or anything similar, in any subfield of C.
--Dan
On Dec 3, 2014, at 4:58 PM, Dan Asimov <dasimov@earthlink.net> wrote:
So we can never have (3/2)^12 = 2^19, or anything similar, in any subfield of C.