Those were nice. One of the slides reminded me that for solving quadratics (-b +- sqrt(b^2-4ac))/2a = 2c/(-b -+ sqrt(b^2-4ac)), so better precision for the two roots can be obtained by picking one root from each side so that both can have the sign of the sqrt same as -b. (And then it's easy to see the RHS root approaching -c/b as a->0.) I don't remember where I first saw this trick, but I've certainly made use of it many times. --ms -----Original Message----- From: math-fun-bounces@mailman.xmission.com [mailto:math-fun-bounces@mailman.xmission.com]On Behalf Of Jason Sent: Sunday, July 27, 2008 14:21 To: math-fun@mailman.xmission.com Subject: [math-fun] Presentation on floating point implementation I thought these slides were well-paced and interesting: http://www.research.scea.com/gdc2003/fast-math-functions_p1.pdf http://www.research.scea.com/gdc2003/fast-math-functions_p2.pdf _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun