On 8/8/2015 10:19 PM, Bill Gosper wrote:
2F1[rational,rational,1 or 1/2,x] ==algebraic1[x] EllipticK[algebraic2[x]] identities? Or at least any more than a,b,c =
Did you try FunctionExpand[Hypergeometric2F1[1/4 - 2, 1/4 + 1, 1 + 3, x]] FunctionExpand[Hypergeometric2F1[1/4 - 2, 3/4 + 1, 1/2 + 3, x]] FunctionExpand[Hypergeometric2F1[1/8 + 4, 5/8 - 2, 1 + 1, x]] etc. --Sasha
1/2,1/2,1 1/4,1/2,1 1/4,3/4,1 1/4/1/4,1 1/4,1/4,1/2 1/4,3/4,1/2 (sort of) 1/8,5/8,1 1/12,7/12,1 ? This last one features seriously unwieldy cubics. Tnx, --rwg
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