14 Dec
2007
14 Dec
'07
12:18 p.m.
Forget those minus ones and try B = 256, C = 320, D = 1512. R. [r = 32, s = 64, t = 8, u = 5] On Fri, 14 Dec 2007, Richard Guy wrote:
Apologies for the hasty rubbish, below. At risk of sending more, how about:
B = rt, C = su, D = (r-u)(s-t) - 1 which
yield(?) A = tu - rs - 1, I hope! R.
On Fri, 14 Dec 2007, Richard Guy wrote:
A^2 = (6+17+29)^2 - 4*6*17 = 52^2 - 408 = 50^2
On Fri, 14 Dec 2007, Robert Baillie wrote:
can the numbers 6, 17, 29 be changed so that the area of "?" becomes an integer?