Re: [math-fun] Incomplete Beta identity?

16 Jun 2011


      Thanks Gene, it's obvious by changing variables in one of the integrals. For
the same reason:

Beta[x, b, a] + Beta[1 - x, a, b] == Beta[a, b]   for 0<x<1.

--Neil Bickford

On Thu, Jun 16, 2011 at 5:03 PM, Neil Bickford <techie314@gmail.com> wrote:
...
Bill and I just found this beta identity and don't recognize it:
Beta[1-x,n,n]+Beta[x,n,n]==2^(1-2 n) Beta[1/2,n]
--Neil Bickford