14 Mar
2009
14 Mar
'09
7:59 p.m.
This *must* be a come-on--it's too stupid to be real: (c2) cfexpand([3,7,15,1,292/2]) [ 52163 355 ] (d2) [ ] [ 16604 113 ] (c3) dfloat(%[1]/%[2]-%pi) (d3) [- 2.66213257216208d-7, 2.66764189404967d-7]
Quoting Jason <jason@lunkwill.org>:
John McKiernan was the earliest to submit 6,283,185,307/2,000,000,000.
Do I see a pattern here? with all the zillion digits of pi, there are probably some prime numbers lurking as subsequences here and there. From then on, it's off to win a prize!
- hvm Who needs primes? Just reduce the fractions.