Okay, thanks for the clarification. I wasn't following the thread closely, and it seemed likely that people are well aware of what I wrote, but I sent it to one person just in case. Jerry Shurman On 5/9/19, Mike Stay <metaweta@gmail.com> wrote:
Of course, but that's a condition on a, not directly on A. It's like saying "exp(z) equals its conjugate when exp(z) is real" rather than "exp z equals its conjugate when Im(z) is an integer multiple of pi".
On Wed, May 8, 2019 at 8:32 PM <bradklee@gmail.com> wrote:
a_{p1^m1 p2^m2 ... p^m} = a_{p1^m1} a_{p2^m2} ... a_{p^m}
?? —Brad
On May 8, 2019, at 8:31 PM, Mike Stay <metaweta@gmail.com> wrote: Are there results on when it does?
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