[math-fun] dragun[2x]/dragun[x] = {1 - I}

(0≤x≤½) What about dragun[5x]? In[347]:= dragun[5/6]/dragun[1/6] Out[347]= {-1 - 2 I} In[348]:= dragun[5/12]/dragun[1/12] Out[348]= {-1 - 2 I} In[349]:= dragun[5/8]/dragun[1/8] Out[349]= {-1 - 2 I} In[350]:= dragun[5/7]/dragun[1/7] Out[350]= {-I} Dang. In[351]:= dragun[2/7]/dragun[1/7] Out[351]= {1 - I} --rwg