22 Aug
2010
22 Aug
'10
6:39 p.m.
On Sun, Aug 22, 2010 at 5:13 PM, Fred lunnon <fred.lunnon@gmail.com> wrote:
Not this time round, alas --- the only solution of (y(x) - 3)^3 = 0 is y = 3; and the Taylor coefficients of exp(3 x) are obviously small and non-integer.
Well, I'm not sure if there's something else going on with the lgdegf here -- I certainly confused myself earlier when I tried to figure it out. But doesn't the e in egf tell us that the sequence is supposed to be n! times the coefficient of x^n? So at least you have integers, even if it is simply the sequence 3^n. And maybe we're supposed to be solving y'/y = (y-3)^3? I continue to confuse myself with the lgd part of this expression. --Joshua