Hello Math-Fun, Let's call 'heterodigital' an integer that doesn't show two identical digits, like 1, 2, 83, 2340, ... An heterodigital doublet is made of two integers whose concatenation is also heterodigital : (123;46) is an heterodigital doublet (123;41) is not. Find all heterodigital triplets (a;b;c) such that a, b, c, s, and p is an heterodigital quintuplet (s = sum = a+b+c and p = product = a*b*c ) A few such examples: a b c s p 1;2;4 7 8 2;4;7 13 56 5;6;8 19 240 There is at least one such quintuplet which is heteropandigital (all digits from 0-->9 are used) Best, É. --- P.-S. I would love to see an equivalent search for all heterodigital quadruplets (a;b;s;p) A sub-list of this being (a;b;s;p;e) where e = exp = a^b examples: (2;3;5;6;8) and (3;2;5;6;9)