Re: [math-fun] Question about summation of 1/P(n) where P(x) is an integer polynomial

1/(n*(n+1)) = 1/n - 1/(n+1) sum(1/(n*(n+1)), n=1..inf) = sum(1/n - 1/(n+1), n=1..inf) = 1 --  Gene On Sunday, February 14, 2021, 1:28:53 PM PST, Dan Asimov <asimov@msri.org> wrote: Suppose P(x) is a polynomial with integer coefficients. Assume that no positive integer is a root of P(x). Is it possible that   Sum 1/P(n)  =  1 where n = 1, 2, 3, ..., runs through the positive integers? —Dan