Re: [math-fun] e^(iπ)

I've always gone with e^(iπ) + 1 = 0. Not only does it have the five fundamental constants, 0, 1, e, π, i It also uses the three fundamental operators +, *, ^

-----Original Message----- From: math-fun [mailto:math-fun-bounces@mailman.xmission.com] On Behalf Of Bill Gosper Sent: Friday, January 18, 2019 9:12 PM To: math-fun@mailman.xmission.com Subject: [math-fun] e^(iπ)

At the risk of a protracted and rancorous political dispute, I'd like an informal vote on which is most "beautiful": e^(iπ) = -1 or e^(iπ) + 1 = 0 ? —rwg I get polarized just thinking about it. _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com https://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun