Re: [math-fun] Describe f(a/b)=a/(b+1)?

Of course, integral Hausdorff dimension = n doesn't have to mean something is a normal n-manifold. E.g., The 2D Cantor set obtained by removing middle p's (with 0 < p < 1) . . . meaning removing the plus-sign-shaped 5p^2 fraction of a square, iteratively, results in a set with Hausdorff dimension d satisfying 1 = 4 ((1-p)/2)^d, which if my arithmetic is correct implies that d = 1 for p = 1/2. Yet this middle-1/2 2D Cantor set is quite fractally. --Dan Andy wrote: ----- [Marc wrote]: << It¹s sure ³bumpy², but is it ³fractally²? Not sure what you mean. The Hausdorff dimension of the graph is 1, if that's what you're asking. -----