Michael Kleber's comment
 
<<
. . . (Pretending that pi is a string of random digits
and other such falsities...)
>>
 
got me thinking.  Suppose we have a probability distribution D
on the set S of all countable sequences of decimal digits. 
 
And suppose that for all *finite* sets of indices {i_1 < ... < i_n},
the corresponding marginal distribution is uniform on {0,...,9}^n. 
 
1.    Does it then follow that D is uniform on S ??? 
 
1a.    Is there a way countably many variables can be correlated
even if no finite subset of them are?
 
Related question:
 
I like considering numbers' "digits" in "factorial" base.
For x in [0,1], I mean by this writing
 
    x = a_1/2! + a_2/3! + ... + a_n/(n+1)! + ...
 
where each a_n is an integer such that 0 <= a_n <= n.  Luckily,
1/2! + 2/3! + 3/4! ... = 1/2 + 1/3 + 1/8 + 1/30 + 1/144 +... = 1.
 
2.    Is pi normal to the factorial base?  Here I mean only the fractional
part of pi.  I.e., for any finite set of indices {i_1 < i_2 < ... <  i_n},
does the joint distribution on
             
                     a_(k + i_1)/(k + i_1+1)! , , ... , a_(k + i_n)/(k+i_n+1)!
 
approach a uniform cdf on [0,1]^n as k -> oo ? 
 
N.B. It's easy to check that e would definitely NOT be normal to the
factorial base.
 
--Dan