10 Jan
2007
10 Jan
'07
1:40 a.m.
My conjecture is that in a 3-way sum, at most two of the cubes can be cubes of primes. ----- Original Message ----- From: "Christian Boyer" <cboyer@club-internet.fr> To: "'math-fun'" <math-fun@mailman.xmission.com> Sent: Wednesday, January 10, 2007 3:08 AM Subject: RE: [math-fun] Taxicab and prime numbers Worst! It seems impossible to find solutions of the more general equations: (5) p^3 + q^3 = r^3 + s^3 = m^3 + n^3 or (6) p^3 +/- q^3 = r^3 +/- s^3 = m^3 +/- n^3 with p, q, r, s primes m, n integers (primes or non-primes) Why? Christian.