RE: [math-fun] x^n + y^n = z^n + w^n

Well, it makes 5 a perfect number: 5 = 1 + (2+i) + (2-i). Rich -----Original Message----- From: math-fun-bounces+rschroe=sandia.gov@mailman.xmission.com on behalf of Mike Speciner Sent: Tue 6/20/2006 6:43 AM To: 'math-fun' Subject: RE: [math-fun] x^n + y^n = z^n + w^n In order to further avoid the +- issue, which anyway doesn't help for even n, what about allowing Gaussian integers? The equation then becomes sum(x[k]^n) = 0. Do [more] non-trivial solutions magically appear? --ms _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com http://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun