In a recent Math Intelligencer, AS Landsberg posed a variation on Monte Hall [paraphrased]: There are three doors, behind which are a car, a car key and a goat. There are two players, the car-player and the key-player. Each player gets to pick two doors to see if they can find their corresponding prize. Each player acts independently and with no information from the other. If they can each find their corresponding prize, the two drive off in their new car. He mentions a proof that with a sufficiently clever strategy the two will be able to drive off in their car 2/3rds of the time. I just can't see how to make that work! If they each pick randomly, I get the odds of their winning the car as 4/9. It is fairly easy to come up with strategies that up the odds to 1/2. But I just don't see how to get it all the way to 2/3rds. /Bernie\ -- Bernie Cosell Fantasy Farm Fibers mailto:bernie@fantasyfarm.com Pearisburg, VA --> Too many people, too few sheep <--