30 Jul
2016
30 Jul
'16
12:41 p.m.
Mean distinct number for a single trial looks like n*m/(n+m-1) , though I don't have a proof --- and presumably it is well-known anyway? WFL On 7/30/16, David Wilson <davidwwilson@comcast.net> wrote:
Let set S contain n objects, each object having equal probability of being selected. At the end of k selections with replacement, what is the expected number of distinct objects that were selected?
_______________________________________________ math-fun mailing list math-fun@mailman.xmission.com https://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun