19 Feb
2012
19 Feb
'12
9:03 a.m.
Sure -- just let n^3 - (n-1)^3 be sufficiently large as well, no? --Michael On Feb 19, 2012 10:48 AM, "Dan Asimov" <dasimov@earthlink.net> wrote:
In what follows, "cube" means the cube of a positive integer.
It is known that every sufficiently large integer is the sum of distinct cubes. See < http://oeis.org/A001476 >.
QUESTION: Is every sufficiently large integer the sum of *more than one* distinct cubes?
--Dan
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