12 Nov
2017
12 Nov
'17
6:55 p.m.
It was kindly pointed out that in my last e-mail I neglected to square the A_j in RMS(f)^2 = lim_[T —> oo] (1/T) Integral_0 ^T (Sum (A_j)^2 sin(B_j x))^2 dx (now fixed). This did not affect anything else. —Dan