27 Feb
2012
27 Feb
'12
6:04 p.m.
"DA" == Dan Asimov <dasimov@earthlink.net> writes:
DA> James, what does f(z) stand for here? Any function f: C -> C ? DA> Any entire function f: C -> C ? Something else? The goal is any function which takes f: C -> C. Technically, though, it is any function which maps {complex double} -> {complex double}. The current code would end up mapping cases where isnan(f(x)) == true to black. But only because I didn't consider that case. As black is also the mapping of f(z) == 0., that may be a problem. :) I presume it would be better to map NaN to white like inf is? -JimC -- James Cloos <cloos@jhcloos.com> OpenPGP: 1024D/ED7DAEA6