12 Jul
2011
12 Jul
'11
9:22 a.m.
Hi, Using the digits {0, 1} and the complex base -1+i, it's straightforward to show that 1010 = 1+3i. Is there an easy way to go backward? That is, given a complex number in the form a+bi, recover its "binary" representation? I'm immediately interested in the case for bases -1+i and -1-i (digits {0, 1}), but also interested in the general case. Thanks for any help, Kerry Mitchell -- lkmitch@gmail.com www.kerrymitchellart.com