28 Nov
2013
28 Nov
'13
10:01 p.m.
no - the Heisenberg group is a counterexample. It is nonabelian of order p^3; its center is of order p; and the quotient, of order p^2, is abelian. Cris On Nov 28, 2013, at 9:48 PM, Eugene Salamin <gene_salamin@yahoo.com> wrote:
Is the following a theorem?
Let G be a group with center Z. If G/Z is abelian, then G is abelian.
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