30 Jan
2020
30 Jan
'20
9:29 p.m.
Wrong Again! Obviously, we also have asymmetric sums such as r1^n-(r2+r3)^n = 0. Duh! One issue with your model though: how do you set parameters to get z^3=1? It sounds like circular Steiner ellipses would have c = 0, implying only z^3=0. Can f(z) equal a constant? The other obvious, standard model is (z-z1)*(z-z2)*(z-z3)=0, but this is so well-known that... --Brad On Thu, Jan 30, 2020 at 5:57 PM Brad Klee <bradklee@gmail.com> wrote:
I think that these identities define the entire null ring, for example: