22 Nov
2007
22 Nov
'07
10:36 a.m.
Hi Eric, It seems to me that since you used 1! to represent 1 (apparently to get one more symbol), you can do things with parentheses, 0!, 1^2 (either with a caret or a superscript), 0^2, 1^[2^(3^4)], etc., to get an arbitrarily large number of symbols. Kerry On Nov 22, 2007 10:30 AM, Eric Angelini <Eric.Angelini@kntv.be> wrote:
Hello Math-fun,
those equalities are doubly true : 2+3=5 5+1!=6 because they have respectively 5 and 6 symbols, altogether.
-- lkmitch@gmail.com www.fractalus.com/kerry