24 Jun
2017
24 Jun
'17
4:41 a.m.
First rewrite it as f(x) + f(1-1/x) = 1/x Now what happens if you set x = 1-1/y? (This problem relies on a very special property of the function 1-1/x) J.P. On Sat, Jun 24, 2017 at 5:46 AM, Guy Haworth <g.haworth@reading.ac.uk> wrote:
My college magazine includes this challenge:
Find a function f(x) such that for every real x not equal to 0 or 1, we have f(1/x) + f(1-x) = x
It's from Oxford BNC's Konstantin Ardakov.
I guess there's a clue here that 1/x and 1/(1-x) feature in the solution ... but how does one go about this?
Guy
_______________________________________________ math-fun mailing list math-fun@mailman.xmission.com https://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun