23 Apr
2013
23 Apr
'13
12:34 p.m.
On Sun, Apr 21, 2013 at 9:50 AM, Keith F. Lynch <kfl@keithlynch.net> wrote:
Would one expect there to be a (possibly non-unique) solution in some base, eventually, just by chance? If so, I propose the opposite challenge -- finding an "anti-alphametic," an arrangement that has no solution in any base.
The simplest one is A + A = AA; in base B, A < B, so A + A < 2B, so the carry is 1, so A = 1. 1+1 results in a carry only in base 2, which doesn't work, so we're done. Andy