[math-fun] I wonder if this would wiggle the needle

on the milliramanujanometer: Sum[n/(-1 + E^(2*Sqrt[11]*n*Pi)), {n, 1, Infinity}] == 1/24 - 1/(8*Sqrt[11]*Pi) - ((8 - (4*6^(1/3)*(-6127 + 63*Sqrt[33]))/ (8199 + 56809*Sqrt[33])^(2/3) + (99 + 205*Sqrt[33])/(6*(8199 + 56809*Sqrt[33]))^ (1/3))*Gamma[1/22]*Gamma[5/22]*Gamma[3/11]* Gamma[15/22])/(2112*2^(8/11)*Sqrt[11]*Pi^2* Gamma[7/22]*Gamma[10/11]) --rwg