Re: [math-fun] Help with a PowerPowerMod

I wrote:

a(22) mod 81 = 31 -> a(23) = 1889*10^(689*10^((5889*10^((578*10^196-218)/81)-165)/81)-194)-1

Sorry, a(23) = 1889*10^((689*10^((5889*10^((578*10^196-218)/81)-165)/81)-194)/ 81)-1