11 Aug
2015
11 Aug
'15
8:29 a.m.
* Fred Lunnon <fred.lunnon@gmail.com> [Aug 10. 2015 20:17]:
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** Given real number z and polynomial f with rational coefficients such that f(z) = 0 , does it necessarily follow that z is algebraic? **
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SPOILER: The deduction fails when f = 0 identically, so that f(z) = 0 for all z . There now --- that wasn't so difficult, was it?
Aaargh! Of course I guessed wrong. So, "non-rigid algebraic" it is.
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