5 Oct
2007
5 Oct
'07
6:43 p.m.
Bill Gosper: As nearly as I can tell without more careful work, I have found an arrangement of your twelve disks inside the oval. It's not a strictly kosher solution, however, because there are definitely two non-triangular interstices. (Of course I concede that my somewhat sloppy cutting and fitting may have led me astray.) The graph in the attached file depicts the candidate solution. The disks are named 1 to 12 in increasing order of size. The existence of an edge in the graph between two disks implies that they are mutually tangent, and the absence of an edge implies that they are not. Alan Schoen