11 Nov
2009
11 Nov
'09
6:14 p.m.
It's a pleasant exercise to calculate the square root of the complex number a + bi directly (without making use of polar form or trig functions). (Be sure to consider all cases.) But is there a similar formula for the cube root of a + bi ??? --Dan _____________________________________________________________________ "It don't mean a thing if it ain't got that certain je ne sais quoi." --Peter Schickele