9 Aug
2014
9 Aug
'14
2:05 p.m.
I can prove this via plane tetracyclic coordinates. The later conjectures can undoubtedly be decided in the same fashion, for small fixed n . Fred Lunnon On 8/8/14, Bill Gosper <billgosper@gmail.com> wrote:
If the four curvatures are k1, k2, k3, k4, and the bounding circles are k0 and k5, then empirically, k1 + k3 = k2 + k4 = k0 + k5 for some assignment of signs to k0 and k5. --rwg _______________________________________________ math-fun mailing list math-fun@mailman.xmission.com https://mailman.xmission.com/cgi-bin/mailman/listinfo/math-fun